Reverse Integer

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This one was had me stumped for a while. My first solution was similar to the one below, but I first found the size of the int by using

(int)(Math.log(x)/Math.log(10))+1;

LeetCode kept giving me a TimeRanOut Error everytime I tried to do the above, so I had to develop the below solution. In addition, accounting for numbers beyond the scope of an int became a bit tricky to solve.

Full Solution in Java:

public class Solution {
    public int reverse(int x) {
        
        long result = 0;
        
        while(x!=0){
            result = result*10+ x%10;
            x/=10;
        }
        
           if (result > Integer.MAX_VALUE || result < Integer.MIN_VALUE){
                return 0;
           }
        
        
        return (int)result;
    }
}